Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Find the values of other five T-ratios, if
and θ lies in II quadrant.
Text Solution
Verified by ExpertsThe correct answer is:
B
Step 1: Identify Given Information
We know that:
$$\tan \theta = -\frac{3}{4}$$
and that the angle \(\theta\) lies in the second quadrant.
Step 2: Determine the Signs of Trigonometric Ratios in the Second Quadrant
In the second quadrant, the following ratios are positive:
- Sine (\(\sin\))
- Cosine (\(\cos\))
The following ratios are negative:
- Tangent (\(\tan\))
- Cotangent (\(\cot\))
Therefore:\
- \(\sin \theta\) > 0
- \(\cos \theta\) < 0
- \(\tan \theta\) < 0
- \(\sec \theta\) < 0
- \(\csc \theta\) > 0
- \(\cot \theta\) < 0
Step 3: Use the Pythagorean Identity to Find Sine and Cosine
From the tangent ratio, we can form a right triangle where the opposite side is \(3\) and the adjacent side is \(4\). Using Pythagoras' theorem to find the hypotenuse:
$$r = \sqrt{(3^2) + (4^2)} = \sqrt{9 + 16} = \sqrt{25} = 5$$
Step 4: Calculate Sine and Cosine
Therefore, we can now determine:
$$\sin \theta = \frac{3}{5} \quad (\text{positive in II quadrant})$$
$$\cos \theta = -\frac{4}{5} \quad (\text{negative in II quadrant})$$
Step 5: Find Other Ratios
Now we can calculate the other trigonometric ratios:
- \(\csc \theta = \frac{1}{\sin \theta} = \frac{5}{3}\)
- \(\sec \theta = \frac{1}{\cos \theta} = -\frac{5}{4}\)
- \(\cot \theta = \frac{1}{\tan \theta} = -\frac{4}{3}\)
Step 6: Summary of T-Ratios
Therefore, the values of the other five T-ratios are:
- \(\sin \theta = \frac{3}{5}\)
- \(\cos \theta = -\frac{4}{5}\)
- \(\csc \theta = \frac{5}{3}\)
- \(\sec \theta = -\frac{5}{4}\)
- \(\cot \theta = -\frac{4}{3}\)
Thus, the correct answer includes these calculated values.
We know that:
$$\tan \theta = -\frac{3}{4}$$
and that the angle \(\theta\) lies in the second quadrant.
Step 2: Determine the Signs of Trigonometric Ratios in the Second Quadrant
In the second quadrant, the following ratios are positive:
- Sine (\(\sin\))
- Cosine (\(\cos\))
The following ratios are negative:
- Tangent (\(\tan\))
- Cotangent (\(\cot\))
Therefore:\
- \(\sin \theta\) > 0
- \(\cos \theta\) < 0
- \(\tan \theta\) < 0
- \(\sec \theta\) < 0
- \(\csc \theta\) > 0
- \(\cot \theta\) < 0
Step 3: Use the Pythagorean Identity to Find Sine and Cosine
From the tangent ratio, we can form a right triangle where the opposite side is \(3\) and the adjacent side is \(4\). Using Pythagoras' theorem to find the hypotenuse:
$$r = \sqrt{(3^2) + (4^2)} = \sqrt{9 + 16} = \sqrt{25} = 5$$
Step 4: Calculate Sine and Cosine
Therefore, we can now determine:
$$\sin \theta = \frac{3}{5} \quad (\text{positive in II quadrant})$$
$$\cos \theta = -\frac{4}{5} \quad (\text{negative in II quadrant})$$
Step 5: Find Other Ratios
Now we can calculate the other trigonometric ratios:
- \(\csc \theta = \frac{1}{\sin \theta} = \frac{5}{3}\)
- \(\sec \theta = \frac{1}{\cos \theta} = -\frac{5}{4}\)
- \(\cot \theta = \frac{1}{\tan \theta} = -\frac{4}{3}\)
Step 6: Summary of T-Ratios
Therefore, the values of the other five T-ratios are:
- \(\sin \theta = \frac{3}{5}\)
- \(\cos \theta = -\frac{4}{5}\)
- \(\csc \theta = \frac{5}{3}\)
- \(\sec \theta = -\frac{5}{4}\)
- \(\cot \theta = -\frac{4}{3}\)
Thus, the correct answer includes these calculated values.
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